MCQEasyJEE 2025Oxidation States & Ionisation Energies

JEE Chemistry 2025 Question with Solution

Given below are two statements : Statement I : CrO3\mathrm{CrO_3} is a stronger oxidizing agent than MoO3\mathrm{MoO_3} Statement II : Cr(VI)\mathrm{Cr(VI)} is more stable than Mo(VI)\mathrm{Mo(VI)} In the light of the above statements, choose the correct answer from the options given below

  • A

    Statement I is false but Statement II is true

  • B

    Statement I is true but Statement II is false

  • C

    Both Statement I and Statement II are true

  • D

    Both Statement I and Statement II are false

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given:

  • Statement I: CrO3\mathrm{CrO_3} is a stronger oxidizing agent than MoO3\mathrm{MoO_3}
  • Statement II: Cr(VI)\mathrm{Cr(VI)} is more stable than Mo(VI)\mathrm{Mo(VI)}

Find: Which statement is correct.

In the same group of transition metals, the oxidizing power of oxides in higher oxidation states generally decreases down the group, while the stability of higher oxidation states increases for the heavier elements.

For Statement I, chromium and molybdenum belong to Group 6. CrO3\mathrm{CrO_3} contains chromium in the +6+6 oxidation state and MoO3\mathrm{MoO_3} contains molybdenum in the +6+6 oxidation state. Because chromium is smaller and more electronegative, Cr(VI)\mathrm{Cr(VI)} is more readily reduced to lower oxidation states. Therefore, CrO3\mathrm{CrO_3} acts as a stronger oxidizing agent than MoO3\mathrm{MoO_3}. So, Statement I is true.

For Statement II, the higher oxidation state becomes more stable down the group for heavier congeners such as molybdenum. Hence Mo(VI)\mathrm{Mo(VI)} is more stable than Cr(VI)\mathrm{Cr(VI)}. So, Statement II is false.

Therefore, Statement I is true but Statement II is false. The correct option is B.

Detailed Trend-Based Explanation

Given:

  • CrO3\mathrm{CrO_3} and MoO3\mathrm{MoO_3} are oxides of Group 66 elements in high oxidation state.
  • We must test the truth of the two statements.

Find: The correct option based on oxidizing power and stability trends.

Statement I: CrO3\mathrm{CrO_3} is a stronger oxidizing agent than MoO3\mathrm{MoO_3}.

Oxides of transition metals in very high oxidation states tend to show oxidizing character. As we move down the group from chromium to molybdenum, this oxidizing tendency decreases. Thus CrO3\mathrm{CrO_3} is a stronger oxidizing agent than MoO3\mathrm{MoO_3}. Hence Statement I is true.

Statement II: Cr(VI)\mathrm{Cr(VI)} is more stable than Mo(VI)\mathrm{Mo(VI)}.

This is incorrect because for heavier members of the group, higher oxidation states are comparatively more stable. Therefore Mo(VI)\mathrm{Mo(VI)} is more stable than Cr(VI)\mathrm{Cr(VI)}. Hence Statement II is false.

So the correct conclusion is: Statement I is true but Statement II is false, which corresponds to option B.

Common mistakes

  • Assuming that oxidizing power and stability follow the same trend down the group. A species can be a stronger oxidizing agent precisely because its high oxidation state is less stable. Separate the ideas of oxidizing strength and oxidation state stability before judging the statements.

  • Thinking that the heavier element must always be the stronger oxidizing agent. Down the group, higher oxidation states of heavier transition elements are generally more stable, so they are often less eager to get reduced. Compare stability before concluding oxidizing power.

  • Marking Statement II true because both compounds are in the +6+6 oxidation state. The same oxidation number does not imply equal stability across a group. Check periodic trends for Group 66 elements rather than relying only on oxidation number.

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