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MCQMediumJEE Main 2025 · 3 April, Shift 1Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 3 April, Shift 1

Let a line passing through the point (4,1,0)(4,1,0) intersect the line L1:x−12=y−23=z−34L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} at the point A(α,β,γ)A(\alpha, \beta, \gamma) and the line L2:x−6=y=−z+4L_2: x - 6 = y = -z + 4 at the point B(a,b,c)B(a, b, c). Then ∣101αβγabc∣\begin{vmatrix} 1 & 0 & 1\\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} is equal to

  • A

    88

  • B

    1616

  • C

    1212

  • D

    66

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