MCQEasyJEE Main 2025 · 2 April, Shift 1Biot–Savart Law

Physics Question from JEE Main 2025 · 2 April, Shift 1

Let B1B_1 be the magnitude of magnetic field at the center of a circular coil of radius RR carrying current II. Let B2B_2 be the magnitude of magnetic field at an axial distance xx from the center. For x:R=3:4x : R = 3 : 4, B2B1\frac{B_2}{B_1} is:

  • A

    4:54 : 5

  • B

    16:2516 : 25

  • C

    64:12564 : 125

  • D

    25:1625 : 16

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