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MCQEasyJEE Main 2025 · 29 January, Shift 2Hess's Law

Chemistry Question from JEE Main 2025 · 29 January, Shift 2

If

C(diamond)→C(graphite)+X kJ mol−1C(\text{diamond}) \rightarrow C(\text{graphite}) + X \, \text{kJ mol}^{-1} C(diamond)+O2(g)→CO2(g)+Y kJ mol−1C(\text{diamond}) + O_2(g) \rightarrow CO_2(g) + Y \, \text{kJ mol}^{-1} C(graphite)+O2(g)→CO2(g)+Z kJ mol−1C(\text{graphite}) + O_2(g) \rightarrow CO_2(g) + Z \, \text{kJ mol}^{-1}

at constant temperature, then:

  • A

    X=Y+ZX = Y + Z

  • B

    −X=Y+Z-X = Y + Z

  • C

    X=−Y+ZX = -Y + Z

  • D

    X=Y−ZX = Y - Z

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