MCQEasyJEE Main 2024 · 30 January, Shift 2Hess's Law

Chemistry Question from JEE Main 2024 · 30 January, Shift 2

Two reactions are given below: 2Fe(s)+32O2(g)Fe2O3(s),ΔH=822kJ/mol2\text{Fe}(s) + \tfrac{3}{2}\text{O}_2(g) \rightarrow \text{Fe}_2\text{O}_3(s), \quad \Delta H^\circ = -822 \, \text{kJ/mol} C(s)+12O2(g)CO(g),ΔH=110kJ/mol\text{C}(s) + \tfrac{1}{2}\text{O}_2(g) \rightarrow \text{CO}(g), \quad \Delta H^\circ = -110 \, \text{kJ/mol} The enthalpy change (in kJ/mol) for the reaction 3C(s)+Fe2O3(s)2Fe(s)+3CO(g)3\text{C}(s) + \text{Fe}_2\text{O}_3(s) \rightarrow 2\text{Fe}(s) + 3\text{CO}(g) is:

  • A

    492492

  • B

    494494

  • C

    496496

  • D

    498498

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