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NVAMediumJEE Main 2023 · 1 February, Shift 1Hess's Law

Chemistry Question from JEE Main 2023 · 1 February, Shift 1

At 25∘C25^\circ \text{C}, the enthalpy of the following processes are given:

H2(g)+O2(g)→2OH(g) ΔH∘=78 kJ mol−1H_2(g) + O_2(g) \rightarrow 2OH(g) \, \Delta H^\circ = 78\, kJ\, mol^{-1} H2(g)+12O2(g)→H2O(g) ΔH∘=−242 kJ mol−1H_2(g) + \frac{1}{2} O_2(g) \rightarrow H_2O(g) \, \Delta H^\circ = -242\, kJ\, mol^{-1} H2(g)→2H(g) ΔH∘=436 kJ mol−1H_2(g) \rightarrow 2H(g) \, \Delta H^\circ = 436\, kJ\, mol^{-1} 12O2(g)→O(g) ΔH∘=249 kJ mol−1\frac{1}{2} O_2(g) \rightarrow O(g) \, \Delta H^\circ = 249\, kJ\, mol^{-1}

What would be the value of XX for the following reaction?

H2O(g)→H(g)+OH(g) ΔH∘=X kJ mol−1H_2O(g) \rightarrow H(g) + OH(g) \, \Delta H^\circ = X \, kJ\, mol^{-1}

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