MCQEasyJEE 2025Heat Transfer (Conduction, Convection, Radiation)

JEE Physics 2025 Question with Solution

The difference of temperature in a material can convert heat energy into electrical energy. To harvest the heat energy, the material should have:

  • A

    low thermal conductivity and low electrical conductivity

  • B

    high thermal conductivity and high electrical conductivity

  • C

    low thermal conductivity and high electrical conductivity

  • D

    high thermal conductivity and low electrical conductivity

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: A temperature difference in a material is used to convert heat energy into electrical energy.

Find: The required combination of thermal and electrical conductivity for efficient energy harvesting.

This is based on the Seebeck effect, where a temperature difference across a material generates an electric voltage.

For efficient thermoelectric conversion:

  • Low thermal conductivity is needed so that heat does not flow away quickly and the temperature difference is maintained.
  • High electrical conductivity is needed so that the generated charge carriers move easily and electric current is conducted efficiently.

If thermal conductivity is high, the temperature gradient reduces quickly, which weakens the thermoelectric effect. Therefore, the best material should have low thermal conductivity and high electrical conductivity.

The correct option is C.

Stepwise Explanation

Given: Heat energy is to be converted into electrical energy using a temperature difference.

Find: Which material property combination is most suitable.

  1. A temperature difference in a material can generate voltage due to the Seebeck effect.
  2. To keep generating voltage, the material must preserve the temperature gradient across it.
  3. Therefore, the material should have low thermal conductivity, so heat is not transferred too rapidly.
  4. The material should also allow charge to move easily.
  5. Therefore, it should have high electrical conductivity.
  6. Hence, the required combination is low thermal conductivity and high electrical conductivity.

Therefore, the correct option is C.

Common mistakes

  • Choosing high thermal conductivity because heat flow seems desirable. This is wrong because rapid heat flow destroys the temperature gradient needed for the Seebeck effect. Instead, the material should have low thermal conductivity.

  • Focusing only on heat retention and choosing low electrical conductivity. This is wrong because poor electrical conductivity prevents efficient transport of the generated charges. Instead, the material should have high electrical conductivity.

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