MCQEasyJEE Main 2025 · 29 January, Shift 2Sum of Series

Mathematics Question from JEE Main 2025 · 29 January, Shift 2

Let S=N{0}S = \mathbb{N} \cup \{0\}. Define a relation RR from SS to R\mathbb{R} by:

R={(x,y):logey=xloge(25),xS,yR}.R = \left\{ (x, y) : \log_e y = x \log_e \left(\frac{2}{5}\right), x \in S, y \in \mathbb{R} \right\}.

Then, the sum of all the elements in the range of RR is equal to:

  • A

    32\frac{3}{2}

  • B

    53\frac{5}{3}

  • C

    109\frac{10}{9}

  • D

    52\frac{5}{2}

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