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MCQMediumJEE Main 2025 · 29 January, Shift 2Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 29 January, Shift 2

Let a straight line LL pass through the point P(2,−1,3)P(2, -1, 3) and be perpendicular to the lines x−12=y+11=z−3−2andx−31=y−23=z+24.\frac{x - 1}{2} = \frac{y + 1}{1} = \frac{z - 3}{-2} \quad \text{and} \quad \frac{x - 3}{1} = \frac{y - 2}{3} = \frac{z + 2}{4}. If the line LL intersects the yzyz-plane at the point QQ, then the distance between the points PP and QQ is:

  • A

    22

  • B

    10\sqrt{10}

  • C

    33

  • D

    232\sqrt{3}

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