A body of mass m connected to a massless and unstretchable string goes in a vertical circle of radius R under…

Question

A body of mass $$m$$ connected to a massless and unstretchable string goes in a vertical circle of radius $$R$$ under gravity $$g$$. The other end of the string is fixed at the center of the circle. If the velocity at the top of the circular path is $$n\sqrt{gR}$$, where $$n \geq 1$$, then the ratio of the kinetic energy of the body at the bottom to that at the top of the circle is:

Accepted Answer

D. $$\frac{n^2 + 4}{n^2}$$

Answer

A. $$\frac{n^2}{n^2 + 4}$$

Answer

B. $$\frac{n}{n + 4}$$

Answer

C. $$\frac{n + 4}{n}$$

Answer & step-by-step solution

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