MCQEasyJEE Main 2025 · 28 January, Shift 2Faraday's Laws of EMI

Physics Question from JEE Main 2025 · 28 January, Shift 2

A uniform magnetic field of 0.4T0.4 \, \text{T} acts perpendicular to a circular copper disc 20cm20 \, \text{cm} in radius. The disc is having a uniform angular velocity of 10πrad/s10\pi \, \text{rad/s} about an axis through its center and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? (π=3.14\pi = 3.14)

  • A

    0.5024V0.5024 \, \text{V}

  • B

    0.2512V0.2512 \, \text{V}

  • C

    0.0628V0.0628 \, \text{V}

  • D

    0.1256V0.1256 \, \text{V}

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