MCQMediumJEE Main 2025 · 28 January, Shift 2Sum of Series

Mathematics Question from JEE Main 2025 · 28 January, Shift 2

For positive integers nn, if 4an=n2+5n+64 a_n = n^2 + 5n + 6 and Sn=k=1n(1ak)S_n = \sum_{k=1}^{n} \left( \frac{1}{a_k} \right), then the value of 507S2025507 S_{2025} is:

  • A

    540540

  • B

    13501350

  • C

    675675

  • D

    135135

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