MCQEasyJEE Main 2025 · 28 January, Shift 2Basics of Vectors

Mathematics Question from JEE Main 2025 · 28 January, Shift 2

If the components of a=αi^+βj^+γk^\vec{a} = \alpha \hat{i} + \beta \hat{j} + \gamma \hat{k} along and perpendicular to b=3i^+j^k^\vec{b} = 3\hat{i} + \hat{j} - \hat{k} respectively are 1611(3i^+j^k^)\frac{16}{11} (3\hat{i} + \hat{j} - \hat{k}) and 111(4i^5j^17k^)\frac{1}{11} (-4\hat{i} - 5\hat{j} - 17\hat{k}), then α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2 is equal to:

  • A

    1818

  • B

    2626

  • C

    2323

  • D

    1616

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Basics of Vectors questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions