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NVAEasyJEE Main 2025 · 28 January, Shift 1Aryl Halides

Chemistry Question from JEE Main 2025 · 28 January, Shift 1

Consider the following sequence of reactions:

Chlorobenzene →(ii) CO2, H3O+; (iii) NH3, Δ(i) Mg, dry ether A → Br2, NaOH  B\text{Chlorobenzene}\ \xrightarrow[\text{(ii) CO}_2,\ \text{H}_3\text{O}^+;\ \text{(iii) NH}_3,\ \Delta]{\text{(i) Mg, dry ether}}\ \textbf{A}\ \xrightarrow{\ \text{Br}_2,\ \text{NaOH}\ }\ \textbf{B}

11.2511.25 mg of chlorobenzene will produce x×10−1x \times 10^{-1} mg of product B. Consider the reactions result in complete conversion. Given the molar masses of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol−1\text{g mol}^{-1} respectively, the value of xx is:

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