MCQEasyJEE Main 2025 · 24 January, Shift 2Trends in Atomic Radius & Ionisation Energy

Chemistry Question from JEE Main 2025 · 24 January, Shift 2

The successive 55 ionisation energies of an element are 800kJ/mol800 \, \text{kJ/mol}, 2427kJ/mol2427 \, \text{kJ/mol}, 3658kJ/mol3658 \, \text{kJ/mol}, 25024kJ/mol25024 \, \text{kJ/mol} and 32824kJ/mol32824 \, \text{kJ/mol}, respectively. By using the above values, predict the group in which the above element is present:

  • A

    Group 44

  • B

    Group 1414

  • C

    Group 22

  • D

    Group 1313

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