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MCQMediumJEE Main 2025 · 24 January, Shift 2Energy in SHM

Physics Question from JEE Main 2025 · 24 January, Shift 2

A particle oscillates along the xx-axis according to the law, x(t)=x0sin⁡2(πtT)x(t) = x_0 \sin^2 \left( \frac{\pi t}{T} \right), where x0=1 mx_0 = 1 \, \text{m} and TT is the time period of oscillation. The kinetic energy (KK) of the particle as a function of xx is correctly represented by the graph:

  • A

    Graph 1:

    K versus x graph starting from zero at x equals 0, rising to a maximum at x equals one-half, then returning to zero at x equals 1 with a symmetric arch.
  • B

    Graph 2:

    K versus x graph starting from zero at x equals 0, rising sharply to a pointed maximum at x equals one-half, then decreasing symmetrically to zero at x equals 1.
  • C

    Graph 3:

    K versus x graph with high values near x equals 0 and x equals 1, dipping to zero at x equals one-half, forming a symmetric valley.
  • D

    Graph 4:

    K versus x graph with large value at x equals 0, decreasing to a minimum near x equals one-half, then increasing again toward x equals 1 in a U shape.

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