NVAEasyJEE Main 2023 · 13 April, Shift 1Energy in SHM

Physics Question from JEE Main 2023 · 13 April, Shift 1

At a given point of time the value of displacement of a simple harmonic oscillator is given as y=Acos(30)y = A \cos (30^\circ). If amplitude is 40cm40 \, \text{cm} and kinetic energy at that time is 200J200 \, \text{J}, the value of force constant is 1.0×10xNm11.0 \times 10^x \, \text{N} \text{m}^{-1}. The value of xx is _____

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