Jeeify
MCQMediumJEE Main 2025 · 24 January, Shift 1Aldehydes & Ketones

Chemistry Question from JEE Main 2025 · 24 January, Shift 1

The product (A) formed in the following reaction sequence is:

Reaction sequence showing propyne reacting with $$Hg^{2+}, H_2SO_4$$, then HCN, then $$H_2/Ni$$ to form product A, with four structural options shown below.
  • A

    CH3−C(NH2)(CH3)−CH2−OH\text{CH}_3-\text{C}(\text{NH}_2)(\text{CH}_3)-\text{CH}_2-\text{OH}

  • B

    CH3−C(OH)(CH3)−CH2−NH2\text{CH}_3-\text{C}(\text{OH})(\text{CH}_3)-\text{CH}_2-\text{NH}_2

  • C

    CH3−CH2−CH(NH2)−CH2−OH\text{CH}_3-\text{CH}_2-\text{CH}(\text{NH}_2)-\text{CH}_2-\text{OH}

  • D

    CH3−CH2−CH(OH)−CH2−NH2\text{CH}_3-\text{CH}_2-\text{CH}(\text{OH})-\text{CH}_2-\text{NH}_2

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Aldehydes & Ketones questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Aldehydes & Ketones

Related questions