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MCQMediumJEE Main 2025 · 24 January, Shift 1Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 24 January, Shift 1

Let the line passing through the points (−1,2,1)(-1, 2, 1) and parallel to the line x−12=y+13=z4\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z}{4} intersect the line x+23=y−32=z−41\frac{x + 2}{3} = \frac{y - 3}{2} = \frac{z - 4}{1} at the point PP. Then the distance of PP from the point Q(4,−5,1)Q(4, -5, 1) is:

  • A

    55

  • B

    1010

  • C

    565\sqrt{6}

  • D

    555\sqrt{5}

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