MCQEasyJEE Main 2025 · 23 January, Shift 2Electric Potential & Potential Energy

Physics Question from JEE Main 2025 · 23 January, Shift 2

Two charges 7 μC7 \, \mu C and −4 μC-4 \, \mu C are placed at (−7 cm,0,0)(-7 \, cm, 0, 0) and (7 cm,0,0)(7 \, cm, 0, 0) respectively. Given, ϵ0=8.85×10−12 C2N−1m−2\epsilon_0 = 8.85 \times 10^{-12} \, C^2 N^{-1} m^{-2}, the electrostatic potential energy of the charge configuration is:

  • A

    −1.5 J-1.5 \, J

  • B

    −2.0 J-2.0 \, J

  • C

    −1.2 J-1.2 \, J

  • D

    −1.8 J-1.8 \, J

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