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MCQEasyJEE Main 2026 · 21 January, Shift 1Electric Potential & Potential Energy

Physics Question from JEE Main 2026 · 21 January, Shift 1

If an alpha particle with energy 7.7 MeV7.7 \, \text{MeV} is bombarded on a thin gold foil, the closest distance from nucleus it can reach is _____ m\text{m}.

(Atomic number of gold = 7979 and 14πϵ0=9×109\frac{1}{4\pi\epsilon_0}=9\times10^{9} SI units)

  • A

    2.95×10−162.95 \times 10^{-16}

  • B

    3.85×10−143.85 \times 10^{-14}

  • C

    2.95×10−142.95 \times 10^{-14}

  • D

    3.85×10−163.85 \times 10^{-16}

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