MCQEasyJEE Main 2026 · 22 January, Shift 2Electric Potential & Potential Energy

Physics Question from JEE Main 2026 · 22 January, Shift 2

Five positive charges each having charge qq are placed at the vertices of a regular pentagon as shown in the figure. The electric potential VV and the electric field E\vec{E} at the center OO of the pentagon due to these five positive charges are

A regular pentagon with positive charges +q at all five vertices and center O marked inside, with distance r from center to one vertex indicated by an arrow.
  • A

    V=5q4πε0rV = \dfrac{5q}{4\pi\varepsilon_0 r} and E=53q8πε0r2r^\vec{E} = \dfrac{5\sqrt{3}q}{8\pi\varepsilon_0 r^2}\,\hat{r}

  • B

    V=0V = 0 and E=0\vec{E} = 0

  • C

    V=5q4πε0rV = \dfrac{5q}{4\pi\varepsilon_0 r} and E=5q4πε0r2r^\vec{E} = \dfrac{5q}{4\pi\varepsilon_0 r^2}\,\hat{r}

  • D

    V=5q4πε0rV = \dfrac{5q}{4\pi\varepsilon_0 r} and E=0\vec{E} = 0

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