JEE Chemistry 2025 Question with Solution

Given: Propanal reacts with excess formaldehyde in alkali under reflux.

Find: The major organic product.

The reliable conclusion in the solution states that the correct option is C. Under these conditions, successive hydroxymethylation at the $\alpha$-carbon followed by reduction leads to the trimethylol product.

Thus the major product is

$$\text{CH}_3\text{C}(\text{CH}_2\text{OH})_3$$

Therefore, the correct option is C.

Note: The solution text is internally inconsistent: one approach describes aldol chemistry and another mentions crossed Cannizzaro to propanol, but the page explicitly marks C as the correct option. Hence the answer is taken as C from the solution.

Given: the solution's shows the reaction of propanal with excess formaldehyde in alkali and lists four options.

Find: Which option matches the major product.

From the solution:

1. The page explicitly says "The Correct Option is C".
2. The answer key also corresponds to option (3).
3. Although the explanatory text on the page is inconsistent, the final marked answer on the source is option C.

Option C corresponds to

$$\text{CH}_3\text{C}(\text{CH}_2\text{OH})_3$$

So the major product, as extracted from the source, is option C.