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MCQMediumJEE Main 2025 · 23 January, Shift 1Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 23 January, Shift 1

Let P be the foot of the perpendicular from the point Q(10,−3,−1)Q(10,-3,-1) on the line:

x−37=y−2−1=z+1−2\frac{x-3}{7} = \frac{y-2}{-1} = \frac{z+1}{-2}

Then the area of the right-angled triangle PQR, where R is the point (3,−2,1)(3,-2,1), is:

  • A

    9159\sqrt{15}

  • B

    30\sqrt{30}

  • C

    8158\sqrt{15}

  • D

    3303\sqrt{30}

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