If (1/(α+1) + 1/(α+2) + … + 1/(α+1012)) - (1/(2·1) + 1/(4·3) + 1/… | JEE Main 2024 Mathematics PYQ

MCQMediumJEE Main 2024 · 8 April, Shift 1Sum of Series

If $\left(\frac{1}{\alpha+1} + \frac{1}{\alpha+2} + \ldots + \frac{1}{\alpha+1012}\right) - \left(\frac{1}{2\cdot1} + \frac{1}{4\cdot3} + \frac{1}{6\cdot5} + \ldots + \frac{1}{2024\cdot2023}\right) = \frac{1}{2024}$ , then $\alpha$ is equal to:

A
$1011$
B
$1009$
C
$1010$
D
$1012$

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