JEE Chemistry 2024 Question with Solution

Given: Match the complexes with their correct hybridization.

Find: The correct option for the matching.

Use the standard hybridization and geometry of these coordination compounds:

Therefore, the match is:

• A $\rightarrow$ III
• B $\rightarrow$ I
• C $\rightarrow$ IV
• D $\rightarrow$ II

So the correct matching is A-III, B-I, C-IV, D-II.

The correct option is D.

Given: The complexes are to be matched with hybridization types.

Find: Which option gives the correct correspondence.

From the solution content, the geometry-hybridization relations are:

Now apply these to the given complexes:

1. K$_2$[Ni(CN)$_4$] is a square planar nickel complex, so it has $dsp^2$ hybridization.
2. [Ni(CO)$_4$] is tetrahedral, so it has $sp^3$ hybridization.
3. [Co(NH$_3$)$_6$]Cl$_3$ contains the octahedral complex [Co(NH$_3$)$_6$]$^{3+}$, so it corresponds to $d^2sp^3$.
4. Na$_3$[CoF$_6$] contains [CoF$_6$]$^{3-}$, an octahedral outer-orbital complex, so it corresponds to $sp^3d^2$.

Hence the final matching is A-III, B-I, C-IV, D-II, which corresponds to option D.