MCQMediumJEE 2024Isomerism (Structural, Stereoisomerism)

JEE Chemistry 2024 Question with Solution

The total number of stereoisomers possible for the given structure is:

  • A

    88

  • B

    22

  • C

    44

  • D

    33

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: The question asks for the total number of stereoisomers possible for the given structure.

Find: The total number of stereoisomers.

The solution states that the correct option is A and concludes that the correct number of stereoisomers is 88.

From the extracted working, the count is obtained using the stereoisomer formula:

2n2^n

where nn is the number of chiral centers.

One approach in the solution describes using:

2n=22=4×2=82^n = 2^2 = 4 \times 2 = 8

with an additional factor of 22 attributed to geometrical isomerism.

Another extracted approach states that the molecule has three chiral centers, so:

23=82^3 = 8

Although the intermediate descriptions in the solution are inconsistent about the number of chiral centers, both approaches conclude the same final result. Therefore, the correct option is A.

Common mistakes

  • Counting only chiral centers and ignoring possible geometrical isomerism is a common mistake. That undercounts the total stereoisomers. Check whether the structure also allows cis/trans or E/Z forms.

  • Applying 2n2^n mechanically without first identifying the correct number of stereogenic centers is incorrect. Always inspect each tetrahedral carbon carefully before using the formula.

  • Assuming every molecule with multiple chiral centers has fewer isomers because of symmetry can be wrong. Meso reduction applies only when an internal plane of symmetry is actually present.

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