MCQEasyJEE 2024Gauss's Law Applications

JEE Physics 2024 Question with Solution

Five charges +q+q, +5q+5q, 2q-2q, +3q+3q, 4q-4q are situated as shown in the figure. The electric flux due to this configuration through the surface SS is:

  • A

    5qϵ0\frac{5q}{\epsilon_0}

  • B

    4qϵ0\frac{4q}{\epsilon_0}

  • C

    3qϵ0\frac{3q}{\epsilon_0}

  • D

    qϵ0\frac{q}{\epsilon_0}

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Five charges +q+q, +5q+5q, 2q-2q, +3q+3q, and 4q-4q are present. The closed surface SS encloses the charges +q+q, +5q+5q, and 2q-2q.

Find: The electric flux through the surface SS.

Use Gauss's law:

ΦE=Qencϵ0\Phi_E = \frac{Q_{\text{enc}}}{\epsilon_0}

The net enclosed charge is:

Qenc=q+5q2q=4qQ_{\text{enc}} = q + 5q - 2q = 4q

Substituting into Gauss's law:

ΦE=4qϵ0\Phi_E = \frac{4q}{\epsilon_0}

Therefore, the electric flux through the surface SS is 4qϵ0\frac{4q}{\epsilon_0}. The correct option is B.

Charge Enclosure Shortcut

Given: Flux through a closed surface depends only on the charge enclosed by that surface.

Find: The electric flux through SS.

Charges outside the surface do not contribute to net flux through the closed surface in Gauss's law. So only add the enclosed charges:

+q+5q2q=4q+q + 5q - 2q = 4q

Hence,

Φ=4qϵ0\Phi = \frac{4q}{\epsilon_0}

Therefore, the correct option is B.

Common mistakes

  • Including all five charges while applying Gauss's law. This is wrong because electric flux through a closed surface depends only on the enclosed charge. Add only the charges inside SS.

  • Ignoring the sign of negative charges. This is wrong because enclosed charge is an algebraic sum. Use +q+5q2q+q + 5q - 2q, not the sum of magnitudes.

  • Thinking that charges outside the surface make the net flux nonzero through the closed surface. They may affect the field locally, but the net flux through the closed surface is determined only by QencQ_{\text{enc}}.

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