MCQMediumJEE Main 2024 · 4 April, Shift 2Sum of Series

Mathematics Question from JEE Main 2024 · 4 April, Shift 2

The value of

1×22+2×32++100×(101)212×2+22×3++1002×101\frac{1 \times 2^2 + 2 \times 3^2 + \ldots + 100 \times (101)^2}{1^2 \times 2 + 2^2 \times 3 + \ldots + 100^2 \times 101}

is:

  • A

    306305\frac{306}{305}

  • B

    305301\frac{305}{301}

  • C

    3231\frac{32}{31}

  • D

    3130\frac{31}{30}

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