The total number of hydrogen atoms in Product A and Product B is: — Solution | JEE Chemistry

MCQEasyJEE 2024Alkyl Halides

The total number of hydrogen atoms in Product A and Product B is:

A
$8$
B
$9$
C
$10$
D
$11$

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The reaction starts with $\text{CH}_3\text{CH}_2\text{Br}$ and $\text{NaOH}$ . The solution indicates two products: $\text{CH}_2=\text{CH}_2$ and $\text{CH}_3\text{CH}_2\text{OH}$ .

Find: The total number of hydrogen atoms in Product $A$ and Product $B$ .

Reaction scheme showing CH3CH2Br reacting with NaOH to give CH2=CH2 in presence of C2H5OH and CH3CH2OH in presence of H2O.

From the reaction scheme, the two products are:

$\text{CH}_2=\text{CH}_2$
$\text{CH}_3\text{CH}_2\text{OH}$

Count hydrogen atoms in each product.

For $\text{CH}_2=\text{CH}_2$ :

2 + 2 = 4

So, ethene contains $4$ hydrogen atoms.

For $\text{CH}_3\text{CH}_2\text{OH}$ :

3 + 2 + 1 = 6

So, ethanol contains $6$ hydrogen atoms.

Total hydrogen atoms in Product $A$ and Product $B$ :

4 + 6 = 10

Therefore, the total number of hydrogen atoms is $10$ . The correct option is C.

Common mistakes

Counting hydrogen atoms in $\text{CH}_3\text{CH}_2\text{OH}$ as only $5$ is incorrect because the hydrogen of the $\text{OH}$ group must also be included. Count all hydrogen atoms present in the molecular formula.
Using the reactant $\text{CH}_3\text{CH}_2\text{Br}$ instead of the products is incorrect because the question asks for hydrogen atoms in Product $A$ and Product $B$ . Identify the final products first, then count hydrogens.
Confusing Product $A$ and Product $B$ with reagents such as $\text{NaOH}$ or $\text{H}_2\text{O}$ is incorrect. The required count is only for the two organic products shown in the reaction scheme.

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Step-by-step solution

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