MCQEasyJEE Main 2024 · 31 January, Shift 1Velocity & Acceleration

Physics Question from JEE Main 2024 · 31 January, Shift 1

The relation between time tt and distance xx is t=αx2+βxt = \alpha x^2 + \beta x, where α\alpha and β\beta are constants. The relation between acceleration (aa) and velocity (vv) is:

  • A

    a=2αv3a = -2\alpha v^3

  • B

    a=5αv5a = -5\alpha v^5

  • C

    a=3αv2a = -3\alpha v^2

  • D

    a=4αv3a = -4\alpha v^3

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