MCQMediumJEE Main 2024 · 31 January, Shift 1Sum of Series

Mathematics Question from JEE Main 2024 · 31 January, Shift 1

The sum of the series:

(113(12)+14)+(213(22)+24)+(313(32)+34)+\left( \frac{1}{1 - 3\cdot(1^2) + 1^4} \right) + \left( \frac{2}{1 - 3\cdot(2^2) + 2^4} \right) + \left( \frac{3}{1 - 3\cdot(3^2) + 3^4} \right) + \ldots up to 1010 terms

  • A

    45109\frac{45}{109}

  • B

    45109-\frac{45}{109}

  • C

    55109\frac{55}{109}

  • D

    55109-\frac{55}{109}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Sum of Series questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions