MCQMediumJEE Main 2024 · 31 January, Shift 1Limits

Mathematics Question from JEE Main 2024 · 31 January, Shift 1

Evaluate the limit:

limx0[e2sin(x)2sin(x)1x2]\lim_{x \to 0} \left[\frac{e^{2|\sin(x)|} - 2|\sin(x)| - 1}{x^2}\right]

  • A

    is equal to 1-1

  • B

    does not exist

  • C

    is equal to 11

  • D

    is equal to 22

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