Number of geometrical isomers possible for the given structure is/are:
- A
- B
- C
- D
Number of geometrical isomers possible for the given structure is/are:
Correct answer:C
Standard Method
Given: The solution states that the given structure has two double bonds, and each double bond can show geometrical isomerism.
Find: The number of geometrical isomers possible for the given structure.
For each double bond, two geometrical arrangements are possible: cis or trans.
So the total number of possibilities is
Thus, the total number of geometrical isomers is .
Therefore, the correct option is C.
Counting with symmetry note
Given: One part of the solution mentions counting possible configurations using stereochemical choices and then accounting for equivalence.
Find: The number of unique geometrical isomers.
The solution notes an initial count of
but then states that because of symmetry, some configurations are equivalent.
After removing equivalent arrangements, the number of unique geometrical isomers becomes .
Therefore, the number of geometrical isomers possible is , so the correct option is C.
Counting only one double bond. This is wrong because the solution indicates that two double bonds can independently show geometrical isomerism. Count the cis/trans possibility for both double bonds.
Using the maximum stereoisomer formula without checking equivalence. This is wrong because symmetry can make some configurations identical. Remove equivalent configurations before giving the final count.
Treating geometrical isomerism and all stereocenters as the same counting problem. This is wrong because the relevant feature here is the independent cis/trans arrangement of double bonds. Focus on the stereochemical element actually present in the structure.
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