MCQMediumJEE Main 2024 · 30 January, Shift 2Combination of Resistors

Physics Question from JEE Main 2024 · 30 January, Shift 2

Two resistances of 100Ω100\,\Omega and 200Ω200\,\Omega are connected in series with a battery of 4V4\,\text{V} and negligible internal resistance. A voltmeter is used to measure voltage across the 100Ω100\,\Omega resistance, which gives a reading of 1V1\,\text{V}. The resistance of the voltmeter must be:

  • A

    100Ω100\,\Omega

  • B

    200Ω200\,\Omega

  • C

    300Ω300\,\Omega

  • D

    400Ω400\,\Omega

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