MCQEasyJEE 2024Molecular Orbital Theory

JEE Chemistry 2024 Question with Solution

The total number of antibonding molecular orbitals formed from 2s2s and 2p2p atomic orbitals in a diatomic molecule is:

  • A

    11

  • B

    22

  • C

    33

  • D

    44

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The question asks for the total number of antibonding molecular orbitals formed from 2s2s and 2p2p atomic orbitals in a diatomic molecule.

Find: The number of antibonding molecular orbitals.

From the solution, the molecular orbitals formed from these orbitals are listed as

σ2s,  σ2s,  σ2p,  π2px,  π2py,  π2px,  π2py,  σ2p\sigma_{2s},\; \sigma^*_{2s},\; \sigma_{2p},\; \pi_{2p_x},\; \pi_{2p_y},\; \pi^*_{2p_x},\; \pi^*_{2p_y},\; \sigma^*_{2p}

Among these, the antibonding molecular orbitals are

σ2s,  π2px,  π2py,  σ2p\sigma^*_{2s},\; \pi^*_{2p_x},\; \pi^*_{2p_y},\; \sigma^*_{2p}

Therefore, the total number of antibonding molecular orbitals is 44. The correct option is D.

Note: The solution incorrectly discusses the total number of molecular orbitals as 88, but for the asked quantity, the antibonding orbitals are only 44.

Common mistakes

  • Counting the total number of molecular orbitals instead of only the antibonding ones. This is wrong because the question specifically asks for antibonding molecular orbitals. First list all MOs, then count only those marked with *.

  • Forgetting that the two π\pi^* orbitals are degenerate but still count as two separate orbitals. Degeneracy does not reduce the number of orbitals. Count both π2px\pi^*_{2p_x} and π2py\pi^*_{2p_y} separately.

  • Ignoring the antibonding orbital from the 2s2s combination. This is wrong because combining two 2s2s atomic orbitals gives one bonding and one antibonding MO. Include σ2s\sigma^*_{2s} in the count.

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