NVAMediumJEE Main 2024 · 29 January, Shift 2Limits

Mathematics Question from JEE Main 2024 · 29 January, Shift 2

Let the slope of the line 45x+5y+3=045x + 5y + 3 = 0 be 27r1+9r2227r_1 + \frac{9r_2}{2} for some r1,r2∈Rr_1, r_2 \in \mathbb{R}. Then lim⁡x→3(∫3x8t2 dt3r2x2−r2x2−r1x3−3x)\lim_{x \to 3}\left(\frac{\int_{3}^{x} 8t^2\,dt}{\frac{3r_2x}{2} - r_2x^2 - r_1x^3 - 3x}\right) is equal to:

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