MCQEasyJEE Main 2024 · 29 January, Shift 1Potential Energy & Conservative Forces

Physics Question from JEE Main 2024 · 29 January, Shift 1

The potential energy function (in J) of a particle in a region of space is given as U=(2x2+3y3+2z)U = (2x^2 + 3y^3 + 2z). Here xx, yy, and zz are in meters. The magnitude of the xx-component of force (in N) acting on the particle at point P(1,2,3)P(1, 2, 3) m is:

  • A

    22

  • B

    66

  • C

    44

  • D

    88

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