MCQMediumJEE Main 2024 · 27 January, Shift 2Limits

Mathematics Question from JEE Main 2024 · 27 January, Shift 2

If limx03+αsin(x)+βcos(x)+log(1x)3tan2(x)=13\lim_{x\to 0} \frac{3 + \alpha \sin(x) + \beta \cos(x) + \log(1 - x)}{3\tan^2(x)} = \frac{1}{3}, then 2αβ2\alpha - \beta is equal to:

  • A

    22

  • B

    77

  • C

    55

  • D

    11

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