MCQEasyJEE Main 2023 · 15 April, Shift 1Velocity & Acceleration

Physics Question from JEE Main 2023 · 15 April, Shift 1

The position vector of a particle related to time tt is given by

r=(10ti^+15t2j^+7k^) m.\vec r = (10t\,\hat{i}+15t^2\,\hat{j}+7\,\hat{k})\ m.

The direction of net force experienced by the particle is

  • A

    Positive xx-axis

  • B

    Positive yy-axis

  • C

    Positive zz-axis

  • D

    In xyx-y plane

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Velocity & Acceleration questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions