NVAMediumJEE Main 2023 · 15 April, Shift 1Sum of Series

Mathematics Question from JEE Main 2023 · 15 April, Shift 1

If the sum of the series (12−13)+(122−12⋅3+132)+(123−122⋅3+12⋅32−133)+(124−123⋅3+122⋅32−12⋅33+134)+⋯\left(\frac{1}{2}-\frac{1}{3}\right) +\left(\frac{1}{2^2}-\frac{1}{2\cdot3}+\frac{1}{3^2}\right) +\left(\frac{1}{2^3}-\frac{1}{2^2\cdot3}+\frac{1}{2\cdot3^2}-\frac{1}{3^3}\right) +\left(\frac{1}{2^4}-\frac{1}{2^3\cdot3}+\frac{1}{2^2\cdot3^2}-\frac{1}{2\cdot3^3}+\frac{1}{3^4}\right) +\cdots is αβ\dfrac{\alpha}{\beta}, where α\alpha and β\beta are coprime, then α+3β\alpha+3\beta is equal to

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