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MCQEasyJEE Main 2023 · 13 April, Shift 2Velocity & Acceleration

Physics Question from JEE Main 2023 · 13 April, Shift 2

The distance travelled by an object in time tt is given by s=(2.5)t2s = (2.5)t^2. The instantaneous speed of the object at t=5 sect = 5 \, \text{sec} will be:

  • A

    25 m/s25 \, \text{m/s}

  • B

    12.5 m/s12.5 \, \text{m/s}

  • C

    5 m/s5 \, \text{m/s}

  • D

    62.5 m/s62.5 \, \text{m/s}

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