NVAMediumJEE 2023Sum of Series

JEE Mathematics 2023 Question with Solution

Let f(x)=k=1xkf(x) = \sum_{k=1}^{\infty} x^k, where xRx \in \mathbb{R} and f(2)=119f(2) = 119. Then f(2)f(1)f(2) - f(1) is equal to _____.

Answer

Correct answer:10

Step-by-step solution

the solution unavailable

Working could not be extracted from the solution. The answer has been taken from the provided correct answer field as 1010.

Common mistakes

  • Treating the notation k=1xk\sum_{k=1}^{\infty} x^k literally without noticing that the given value f(2)=119f(2) = 119 is inconsistent with an infinite geometric series for x=2x=2. Use the provided answer source when the solution is unavailable.

  • Including units or extra words in the numerical answer. For a numerical value answer, write only the number, so the answer should be entered as 1010 and not with any added text.

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