NVAMediumJEE 2023Sum of Series

JEE Mathematics 2023 Question with Solution

Section – B

The sum to 2020 terms of the series 2.2232+2.4252+2.622.2^2 - 3^2 + 2.4^2 - 5^2 + 2.6^2 - \dots is equal to --.

Answer

Correct answer:1310

Step-by-step solution

Standard Method

Given: The series is

2.2232+2.4252+2.6272+2.2^2 - 3^2 + 2.4^2 - 5^2 + 2.6^2 - 7^2 + \cdots

Find: The sum to 2020 terms.

From the solution, the series is written as

S=n=110(2n+0.2)2(2n+1)2S = \sum_{n=1}^{10} (2n + 0.2)^2 - (2n+1)^2

Expanding,

(2n+0.2)2=4n2+0.8n+0.04(2n + 0.2)^2 = 4n^2 + 0.8n + 0.04

and

(2n+1)2=4n2+4n+1(2n+1)^2 = 4n^2 + 4n + 1

Therefore,

(2n+0.2)2(2n+1)2=3.2n0.96(2n + 0.2)^2 - (2n+1)^2 = -3.2n - 0.96

Now summing from n=1n=1 to 1010,

n=110(3.2n)=3.2×10(11)2=176\sum_{n=1}^{10} (-3.2n) = -3.2 \times \frac{10(11)}{2} = -176

and

n=110(0.96)=9.6\sum_{n=1}^{10} (-0.96) = -9.6

Hence,

S=1769.6=185.6S = -176 - 9.6 = -185.6

However, the solution finally states that the correct sum is 13101310. Following the solution's stated conclusion, the answer is 13101310. There is a clear discrepancy between the shown working and the stated final answer.

Discrepancy Noted in Source Solution

Given: The source solution contains intermediate algebra and a final stated answer.

Find: The answer consistent with the solution's.

The intermediate working shown in the working gives

S=n=110[(2n+0.2)2(2n+1)2]=185.6S = \sum_{n=1}^{10} \left[(2n+0.2)^2 - (2n+1)^2\right] = -185.6

But the same source then concludes: "Therefore, the correct sum to the series is 13101310".

Since the extraction rule gives primary source to the solution conclusion, the recorded answer is 13101310. Students should note that the displayed derivation and the final stated answer on the page do not agree.

Common mistakes

  • Treating 2020 terms as 2020 pairs is incorrect. The pattern shown groups into pairs, so 2020 terms correspond to 1010 such grouped differences. Count the terms carefully before forming the summation.

  • Expanding (2n+0.2)2(2n+0.2)^2 incorrectly is a common error. Use

    (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2

    so the middle term must be 0.8n0.8n, not another value.

  • Assuming the final printed answer must match the displayed algebra can mislead you here. Always verify whether the working and conclusion are consistent; in this source they are not, so the discrepancy must be noted explicitly.

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