MCQMediumJEE Main 2023 · 12 April, Shift 1Sum of Series

Mathematics Question from JEE Main 2023 · 12 April, Shift 1

Let an\langle a_n \rangle be a sequence such that a1+a2++an=n2+3n(n+1)(n+2)a_1 + a_2 + \dots + a_n = \frac{n^2 + 3n}{(n+1)(n+2)}. If

28k=1101ak=p1p2p3pm28\sum_{k=1}^{10} \frac{1}{a_k} = p_1p_2p_3 \dots p_m

where p1,p2,,pmp_1, p_2, \dots, p_m are the first mm prime numbers, then mm is equal to:

  • A

    77

  • B

    66

  • C

    55

  • D

    88

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