Which of the following complex has a possibility to exist as meridional isomer?
- A
[Co(en)]Cl
- B
[Pt(NH)]Cl
- C
[Co(en)]
- D
[Co(NH)(NO)]
Which of the following complex has a possibility to exist as meridional isomer?
[Co(en)]Cl
[Pt(NH)]Cl
[Co(en)]
[Co(NH)(NO)]
Correct answer:D
Standard Method
Given: We need to identify which complex can show meridional isomerism.
Find: The complex having the possibility of existing as a meridional isomer.
Facial and meridional isomerism arises in octahedral complexes of the type.
The solution states that the type of compound exists as facial and meridional isomer.

Among the given options, [Co(NH)(NO)] matches the pattern in an octahedral complex.
Therefore, the correct option is D.
Geometry Identification
Given: Meridional isomerism is associated with geometric isomerism in coordination compounds.
Find: Which given complex can form a mer isomer.
For facial-meridional isomerism, the complex must have three ligands of one type and three ligands of another type arranged octahedrally, that is:
Options with three bidentate en ligands do not represent the required arrangement for fac-mer distinction.
The complex [Co(NH)(NO)] has three NH ligands and three NO ligands, so it can exist in fac and mer forms.
Hence, the correct option is D.
Assuming that every octahedral complex shows meridional isomerism is incorrect. Meridional isomerism specifically requires the type arrangement. First check the ligand pattern, then test for fac-mer possibility.
Confusing complexes containing en with complexes is a common error. The ligand en is bidentate, so its coordination pattern is different. Count ligand types and denticity carefully before deciding the isomerism.
Ignoring the condition of geometric isomerism in octahedral coordination compounds leads to wrong choices. Mer and fac forms arise from spatial arrangement of ligands, not only from the molecular formula. Examine the three-dimensional distribution of ligands.
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