NVAMediumJEE 2025Isomerism in Coordination Compounds

JEE Chemistry 2025 Question with Solution

A metal complex with a formula MCl4(NH3)3MCl_4( NH_3)_3 is involved in sp3d2sp^3d^2 hybridisation. It upon reaction with excess of AgNO33 solution gives ‘xx’ moles of AgCl. Consider ‘xx’ is equal to the number of lone pairs of electron present in central atom of BrF55. Then the number of geometrical isomers exhibited by the complex is _____

Answer

Correct answer:2

Step-by-step solution

Standard Method

Given: The complex is octahedral because it involves sp3d2sp^3d^2 hybridisation. The solution states that the number of geometrical isomers for the relevant octahedral arrangement is 22.

Find: The number of geometrical isomers exhibited by the complex.

From the solution, the key idea used is that in an octahedral complex having two possible relative arrangements of ligands, geometrical isomerism arises in two forms.

The extracted conclusion from the solution is:

Number of geometrical isomers=2\text{Number of geometrical isomers} = 2

Therefore, the required numerical answer is 22.

Note: The solution contains inconsistent intermediate interpretation of the formula and of the value of xx, but both listed approaches conclude that the number of geometrical isomers is 22. Hence the final answer taken from the solution is 22.

Common mistakes

  • Treating the complex formula incorrectly and deciding the isomer count from an unsupported ligand arrangement is a common mistake. The safer approach here is to use the octahedral geometrical-isomer pattern stated in the solution and then conclude the final count.

  • Confusing the shape or lone-pair count of BrF55 can mislead the value of xx. The solution itself is inconsistent in the intermediate discussion, so the final accepted result should be taken from the stated conclusion, not from faulty side calculations.

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