JEE Chemistry 2023 Question with Solution

Given: The substrate is reduced with $LiAlH_4$ followed by acidic workup with $H_3O^+$.

Find: The product X formed after reduction.

From the solution, the reaction is analyzed as reduction of the carbonyl-containing substrate, and the final product stated is:

$$\text{H}_2\text{N} - \text{CH}_2\text{OH}$$

The solution explicitly concludes that this is the required product.

However, the solution also says "The Correct Option is B", while the displayed final product matches option D in the given options. Therefore, the worked product structure is taken as authoritative, and the listed option label on the solution appears inconsistent.

Therefore, the correct option is B according to the solution, though the structure matches option D verbatim in the options list.

Given: The answer key marks option (4), and the solution text concludes the product is $\text{H}_2\text{N} - \text{CH}_2\text{OH}$.

Find: Which option should be selected.

Comparing the options:

1. $H_2N - CH_2 - CH_2OH$
2. $H_2N - CH_2 - OH$
3. $H_2N - CH_3$
4. $H_2N - CH_2OH$

The product written in the solution text,

$$\text{H}_2\text{N} - \text{CH}_2\text{OH}$$

matches option D exactly. The "Correct Option is B" line is inconsistent with both the answer key and the written final product.

Because the instruction prioritizes the solution, the returned answer follows the option label explicitly stated there: B.