NVAEasyJEE Main 2023 · 10 April, Shift 2Biot–Savart Law

Physics Question from JEE Main 2023 · 10 April, Shift 2

A straight wire carrying a current of 14A14 \, \text{A} is bent into a semicircular arc of radius 2.2cm2.2 \, \text{cm} as shown in the figure. The magnetic field produced by the current at the centre OO of the arc is _____ ×104T\times 10^{-4} \, T.

A straight horizontal wire is bent upward into a semicircular arc with current flowing from left to right, and the centre O is marked below the arc.

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