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MCQMediumJEE Main 2023 · 8 April, Shift 1Alcohols

Chemistry Question from JEE Main 2023 · 8 April, Shift 1

The major product formed in the following reaction is:

Reaction scheme showing an aromatic fused-ring compound bearing one $$\text{CO}_2\text{H}$$ group and one $$\text{CO}_2\text{Et}$$ group treated with $$\text{LiBH}_4/\text{EtOH}$$ followed by $$\text{H}_3\text{O}^+$$, with four product structures as options.
  • A

    (1) The carboxylic acid is reduced to −CH2OH-\text{CH}_2\text{OH} while the ester (CO2Et)\left(\text{CO}_2\text{Et}\right) is left untouched.

  • B

    (2) Both side chains end in CO2H\text{CO}_2\text{H} groups.

  • C

    (3) Both side chains are reduced to primary alcohols (−CH2OH)\left(-\text{CH}_2\text{OH}\right).

  • D

    (4) The carboxylic acid (CO2H)\left(\text{CO}_2\text{H}\right) is left untouched while the ester is reduced to a primary alcohol (−CH2OH)\left(-\text{CH}_2\text{OH}\right).

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